28. Company you work for employs 12,000 workers assembling TV sets. The average

Question

28. Company you work for employs 12,000 workers assembling TV sets. The average time they assemble a TV set is 18 minutes. You pick one worker and observe that she completed the task in 24 minutes and tht places her 3 standard deviations away from the mean. Assume the assembly times are normally distributed. a) b) c) d) What is the variance of the assembly time for all the workers? Is that particular worker one of the most efficient or least efficient workers? What percent of the workers are expected to take longer? How many workers does are expected to take longer?

Explanation / Answer

Ans:

a)

24-18=3*sd

6=3*sd

sd=2

Variance=2^2=4

b)Least efficient,as taking unusually higher time.

c)

z=(24-18)/2=3

P(z>3)=0.00135 or 0.135%

d)12000*0.00135=16 approximately

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