ENGT-3010 TEST 9/19/2018 Fall 2018 SHOW ALL WORK FOR FULL CREDIT NAME: 1) The da

Question

ENGT-3010 TEST 9/19/2018 Fall 2018 SHOW ALL WORK FOR FULL CREDIT NAME: 1) The data below is from a randomly sampled, normally distributed population 16.4 153 28.1 107 149 22.2 9.6 188 197 18.9 143 164 A) Find the mean, or average of the above values Mean (u)- 8) Find the median of the above values Median C) What is the Range of the Values (Max - Min)? Range Given that the standard deviation of the above population is known to be 5 D) What is the "99.73% Statistical Range" of individuals (mean +/-3 std deviations? Lower to E) What is the probability that X

Explanation / Answer

Solution:- Given that 15.3,28.1,10.7,14.9,22.2,9.6,18.8,19.7,18.9,14.3,16.4

A) Mean = sum of items/total number of items = 188.9/11 =17.17

b) Median = 16.4
Explanation

The median is the middle number in a sorted list of numbers. So, to find the median, we need to place the numbers in value order and find the middle number.

Ordering the data from least to greatest, we get:

9.6 10.7 14.3 14.9 15.3 16.4 18.8 18.9 19.7 22.2 28.1

So, the median is 16.4 .

C)
Range : 18.5
Explanation

The range is the difference between the highest and lowest values in the data set.

Ordering the data from least to greatest, we get:

9.6 10.7 14.3 14.9 15.3 16.4 18.8 18.9 19.7 22.2 28.1

The lowest value is 9.6.

The highest value is 28.1.

The range = 28.1 - 9.6 = 18.5.

D) => X +/- 3*s => 17.17 +/- 3*5.1 = (1.87 , 32.47)

E) => P(X < 10) = P(Z < X - mean)/sd
= P(Z < (10 - 17.17)/5.1)
= P(Z < -1.4058)
= 0.0793
f) X = 17.17 + (5.1*1.645) = 25.5595

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