a one-factor ANOVA. either a one-factor ANOVA or a two-tailed t -test. a t -test
ID: 3072139 • Letter: A
Question
a one-factor ANOVA.
either a one-factor ANOVA or a two-tailed t-test.
a t-test for two means from paired (related) samples.
a t-test for two means from independent samples.
2) To test the null hypothesis H0: 1 = 2 = 3 using samples from normal populations with unknown but equal variances, we:
would need three-factor ANOVA.
cannot safely use ANOVA.
can safely employ ANOVA.
would prefer three separate t-tests.
6.91.
3.24.
2.06.
2.56.
4)
6.
4.
2.
3.
5)
8.
11.
9.
2.
6)
11.
2.
3.
9.
7)
Med 3, Med 4
Med 1, Med 2
None of them.
Med 2, Med 4
8)
1.
impossible to determine.
2.
3.
Day Class Night Class 93 74 85 85 60 82 73 91 8 1Explanation / Answer
1)a t-test for two means from paired (related) samples.
Because, the two groups are related, we should use t-test for for two means form paired samples.
2)can safely employ ANOVA.
To compare three means, with equal but unknown variances, we should one -way ANOVA.
3)Here, df og treatment = SS/MSS= (44757/11189)=4
So, F(4,59) at 0.05 is 2.56
4)SS for between groups = Total SS-SS for within groups=2113.833-1483=630.833
and df for between groups = SS/MSS = (630.833/210.2778)=3
And we know that, df= no of groups-1
=> no of groups = df+1 =3+1 =4
Df for within groups = SS/MSS=1483/74.15 =20
Total df= 3+20 =23
Total no of observations = 23+1=24
Since, there are 4 groups, each groups must have 6 observations.
Ans:- 6.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.