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a one-factor ANOVA. either a one-factor ANOVA or a two-tailed t -test. a t -test

ID: 3072139 • Letter: A

Question

a one-factor ANOVA.

either a one-factor ANOVA or a two-tailed t-test.

a t-test for two means from paired (related) samples.

a t-test for two means from independent samples.

2) To test the null hypothesis H0: 1 = 2 = 3 using samples from normal populations with unknown but equal variances, we:

would need three-factor ANOVA.

cannot safely use ANOVA.

can safely employ ANOVA.

would prefer three separate t-tests.

6.91.

3.24.

2.06.

2.56.

4)

6.

4.

2.

3.

5)

8.

11.

9.

2.

6)

11.

2.

3.

9.

7)

Med 3, Med 4

Med 1, Med 2

None of them.

Med 2, Med 4

8)

1.

impossible to determine.

2.

3.

Day Class Night Class 93 74 85 85 60 82 73 91 8 1

Explanation / Answer

1)a t-test for two means from paired (related) samples.

Because, the two groups are related, we should use t-test for for two means form paired samples.

2)can safely employ ANOVA.

To compare three means, with equal but unknown variances, we should one -way ANOVA.

3)Here, df og treatment = SS/MSS= (44757/11189)=4

So, F(4,59) at 0.05 is 2.56

4)SS for between groups = Total SS-SS for within groups=2113.833-1483=630.833

and df for between groups = SS/MSS = (630.833/210.2778)=3

And we know that, df= no of groups-1

=> no of groups = df+1 =3+1 =4

Df for within groups = SS/MSS=1483/74.15 =20

Total df= 3+20 =23

Total no of observations = 23+1=24

Since, there are 4 groups, each groups must have 6 observations.

Ans:- 6.

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