A bag contains 8 red marbles, 7 white marbles, and 6 blue marbles. Randomly choo

Question

A bag contains 8 red marbles, 7 white marbles, and 6 blue marbles. Randomly choose two marbles, one at a time, and without replacement. Find the following. Enter your answers as fractions or decimals rounded to three decimal places. Part 1 The probability that the first marble is red and the second is blue. P (first red and second blue-l.114 Part 2 The probability that both are the same color. P(same color)- 305 Part 3 out of 3 The probability that the second marble is white. P (second marble white)- CHECK NEXT

Explanation / Answer

Part - 3: Here we need to make two cases:

Case - I: First marble was white. Then,

P(Second marble was white) = (7/21)*(6/20) = 0.10

Case - II: First marble was not white. Then,

P(Second marble was white) = (14/21)*(7/20) = 0.233

Hence,

Required probability = 0.233 + 0.10 = 0.333

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