probobility problems please show how it works. 1. 2. 3. A poker hand contains fi

Question

probobility problems please show how it works.

1.

2.

3.

A poker hand contains five cards. Find the probability that a poker hand be: a. "four of a kind" (contains four cards of equal face value); b. "full house" (three cards of equal face value and two others of equal face value); c. "three of a kind" (three cards of equal face value and two cards with face values different from the three and from each other); d. "one pair" (two cards of equal face value and three cards with face values different from the two and from each other); e. "two pairs" (two cards of equal face value, two other cards of equal face value different from the value of the first two, and one card with face value different from each of the other four)

Explanation / Answer

#2.
There will be 12 spaces between 11 '#' signs.
8 '*' can be arranged in these spaces in 12C8 ways

Required number of ways are 12C8 = 495

#3.
P(A) = 13C1/52C1 = 1/4 = 0.25

P(B) = 13C1/52C1 * 13C1/52C1 + 39C1/52C1 * 13C1/52C1
= (13/52)^2 + 39*13/52^2
= 0.25

P(C) = 26C1/52C1*26C1/52C1 + 26C1/52C1*26C1/52C1
= (1/2)^2 + (1/2)^2
= 0.5

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.