Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

The ages of the winners of a cycling tournament are approximately bell-shaped. T

ID: 3074499 • Letter: T

Question

The ages of the winners of a cycling tournament are approximately bell-shaped. The mean age is

27.527.5

years, with a standard deviation of

3.53.5

years. The winner in one recent year was

3232

years old.

(a) Transform the age to a z-score.

(b) Interpret the results.

(c) Determine whether the age is unusual.

(a) Transform the age to a z-score.

z equalsz=nothing

(Type an integer or decimal rounded to two decimal places as needed.)

(b) Interpret the results.

An age of

3232

is about

nothing

standard deviation(s)

belowbelow

aboveabove

the mean.

(Type an integer or decimal rounded to two decimal places as needed.)

(c) Determine whether the age is unusual. Choose the correct answer below.

A.

Yes comma this value is unusual.Yes, this value is unusual.

A z-score outside of the range from minus 2 to 2 is unusual.outside of the range from 2 to 2 is unusual.

B.

No comma this value is not unusual.No, this value is not unusual.

A z-score

outside of the range from minus 2 to 2 is notoutside of the range from 2 to 2 is not

unusual.unusual.

C.

No comma this value is not unusual.No, this value is not unusual.

A z-score between minus 2 and 2 is not unusual.between 2 and 2 is not unusual.

D.

Yes comma this value is unusual.Yes, this value is unusual.

A z-score

between minus 2 and 2 is unusual.between 2 and 2 is unusual.

Explanation / Answer

a)
Z=(X-mean)/sd
=(32-27.5)/3.5=1.2857
z=1.2857

b) An age of 32 is about 1.2857 standard deviation above then mean.

c)
(C) No, this value is not unusual. A z-score between minus 2 and 2 is not unusual

..........................

if you have any doubt ask in comment give thumbs up if you like work.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote