A) y = C1[(x)(cos ln x)] + C2[(x)(sin ln x)] B) y = C1[(x)(cos ln x2)] + C2[(x)(

Question

A) y = C1[(x)(cos ln x)] + C2[(x)(sin ln x)]
B) y = C1[(x)(cos ln x2)] + C2[(x)(sin ln x2)]
C) y = C1[(x)(cos ln x3)] + C2[(x)(sin ln x3)]
D) y = C1[(1/x)(cos ln x)] + C2[(1/x)(sin ln x)]
E) y = C1[(1/x)(cos ln x2)] + C2[(1/x)(sin ln x2)]
F) y = C1[(1/x)(cos ln x3)] + C2[(1/x)(sin ln x3)]
G) y = C1[(x2)(cos ln x)] + C2[(x2)(sin ln x)]
H) y = C1[(x2)(cos ln x2)] + C2[(x2)(sin ln x2)]
I) y = C1[(x2)(cos ln x3)] + C2[(x2)(sin ln x3)]
J) y = C1[(1/x2)(cos ln x)] + C2[(1/x2)(sin ln x)]
K) y = C1[(1/x2)(cos ln x2)] + C2[(1/x2)(sin ln x2)]
L) y = C1[(1/x2)(cos ln x3)] + C2[(1/x2)(sin ln x3)]
M) none of these

Explanation / Answer

I) y = C1[(x2)(cos ln x3)] + C2[(x2)(sin ln x3)]

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