The gene pairs Aa, Bb, and Cc each affect a different trait. In each case, the u
ID: 308940 • Letter: T
Question
The gene pairs Aa, Bb, and Cc each affect a different trait. In each case, the uppercase letter signifies the dominant allele and the lowercase letter the recessive allele. The gene pairs assort independently of one another. Show your work in calculating the probability of obtaining: an Aa BB Cc zygote from a cross of individuals that are Aa Bb Cc times Aa Bb Cc an Aa BB cc zygote from a cross of individuals that are aa BB cc times AA bb CC an A_B_C phenotype from a cross of individuals that are Aa BbCC times Aa Bb cc an a_b_c phenotype from a cross of individuals that are Aa Bb Cc times aa Bb ccExplanation / Answer
Answer:
a) Aa BB Cc zygote from individuals Aa Bb Cc x Aa Bb Cc, and genes are independently assorted.
Aa
Aa x Aa = AA, Aa,Aa,aa
The chance for Aa = 2/4
similarly for BB
BbxBb = BB, Bb, Bb,bb
BB = 1/4
for Cc =
Cc xCc = CC,Cc,Cc,cc
Cc= 2/4
The probability = 1/2 x 1/4 x1/2
= 1/16
b) . Aa BB cc zygote from a cross of an individual aa BB Cc x AA bb CC
The formation of
Aa= 1/1
BB= 0/1
cc= 0/1
The probabilty is zero, so there is nochance for Aa BB cc
c) A_B_ C_ phenotype from a cross of Aa Bb CC x Aa Bb cc
A_ = 3/4
B_ = 3/4
C_ =1/1
The probability = 3/4 x 3/4 x 1 = 9/16
d) a_b_c_ phenotype from a cross between individual sof AA BB CC x AA BB CC
AA x AA, BBxBB, CC xCC ;
all are dominant individuals so, nochance for recessive individuals.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.