Can you help me with the following: a) -x=33, need to use multiplicationprincipl

Question

Can you help me with the following: a) -x=33, need to use multiplicationprinciple   b)2/13x =10   this is two thirdsx = 1= c)7[9-7(8-q)]-9 = 9[7(9q-8)+6] -82    what is solution? and is it n=no solution or R= real number? d)8y=3x    what is y? e) c=yw+y what is w? Can you help me with the following: a) -x=33, need to use multiplicationprinciple   b)2/13x =10   this is two thirdsx = 1= c)7[9-7(8-q)]-9 = 9[7(9q-8)+6] -82    what is solution? and is it n=no solution or R= real number? d)8y=3x    what is y? e) c=yw+y what is w?

Explanation / Answer

a) -x=33, need to use multiplicationprinciple   b)2/13x =10   this is two thirdsx = 1= c)7[9-7(8-q)]-9 = 9[7(9q-8)+6] -82    what is solution? and is it n=no solution or R= real number? d)8y=3x    what is y? e) c=yw+y what isw?                                       PLEASE RATE
: a)-x=33 :
x=-33..........multiply both sides by-1 :
b)(2/13)x=10 :
x=10(13/2)=65.........multiplied bothsides by 13/2 to isolate x :
c)7[9-7(8-q)]-9 = 9[7(9q-8)+6] -82     : 7(9-56+7q)-9=9(63q-56+6)-82 :
63-392+49q-9=567q-504+54-82 : 49q-338=567q-532 518q=194 : q=194/518=92/259.........q=Realnumber : d)8y=3x    what is y? y=(3/8)x.........divided both sidesby 8 to isolate y : e) c=yw+y what is w? : c=y(w+1) :
w+1=c/y----->divided both sides by y :
w=(c/y)-1--->subtracted 1 from bothsides

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