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#10 Solve the problem about two-digit numbers. When the digits of a two-digit nu

ID: 3090160 • Letter: #

Question

#10 Solve the problem about two-digit numbers.
When the digits of a two-digit number are reversed, the newnumber is 54 less than the original number. If the sum of itsdigits is 8, what is the original number?
#16 Solve by using a system of 2 equations in 2variables.
The denominator of a fraction is 9 more than the numerator. Ifthe numerator is decreased by 3 and the denominator is increased by3, the value of the resulting fraction is 1/4. What is the originalfraction?
#18 PLEASE HELP!!!
If the numerator of a fraction is increased by 4, the value ofthe resulting fraction is 3/4. If the denominator of the originalfraction is increased by 2, the value of the resulting fraction is1/2. Find the original fraction. Solve the problem about two-digit numbers.
When the digits of a two-digit number are reversed, the newnumber is 54 less than the original number. If the sum of itsdigits is 8, what is the original number?
#16 Solve by using a system of 2 equations in 2variables.
The denominator of a fraction is 9 more than the numerator. Ifthe numerator is decreased by 3 and the denominator is increased by3, the value of the resulting fraction is 1/4. What is the originalfraction?
#18 PLEASE HELP!!!
If the numerator of a fraction is increased by 4, the value ofthe resulting fraction is 3/4. If the denominator of the originalfraction is increased by 2, the value of the resulting fraction is1/2. Find the original fraction.

Explanation / Answer

#10 let the 2 digit number be ab which can be written as10a+b....the reverse is ba which can be written as 10b+a : 10b+a=10a+b-54.....eq 1 a+b=8.........................eq 2 : rewrite eq 2 to a=8-b and plug it into eq 2 : 10b+8-b=10(8-b)+b-54 : 9b+8=80-10b+b-54 :
18b=18 : b=1 : a=8-b=8-1=7 : so the number is 71 : #16 x-3/(x+9+3)=1/4 :
x-3/(x+12)=1/4---->4(x-3)=x+12--->4x-12=x+12--->3x=24--->x=8 :