y 3_ 12+3y-4y 2 = well i solved it like thisy 3 -4y 2 +3y-12 y 2 (y-4) +3(y-4) m

Question

                                                  y3_12+3y-4y2 =      well i solved it like thisy3-4y2+3y-12                          y2 (y-4) +3(y-4) my answer was = (y-4) (y2+3), but the booksays the answer = (y2+3)(y-4) does that mean thatit does matter which goes first or does that mean the higheresponent goes alwast first?? or did i solve it wrong???                                                   y3_12+3y-4y2 =      well i solved it like thisy3-4y2+3y-12                          y2 (y-4) +3(y-4) my answer was = (y-4) (y2+3), but the booksays the answer = (y2+3)(y-4) does that mean thatit does matter which goes first or does that mean the higheresponent goes alwast first?? or did i solve it wrong???

Explanation / Answer

You answer (y-4) (y2+3) is right but its morecorrect to write it like this (y2+3)(y-4) by puting the() with the highest X power first

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