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factor x 9 +y 9 i tried solving it = cubes so i solved like this(x 3 ) 3 +(y 3 )

ID: 3090441 • Letter: F

Question

                   factor      x9+y9 i tried solving it = cubes so i solved like this(x3)3+(y3)3 then(x3+y3)(x6-x3y3+y6)but the book says the answer is(x+y)(x2-xy+y2)(x6-x3y3+y6) '                    factor      x9+y9 i tried solving it = cubes so i solved like this(x3)3+(y3)3 then(x3+y3)(x6-x3y3+y6)but the book says the answer is(x+y)(x2-xy+y2)(x6-x3y3+y6) ' i tried solving it = cubes so i solved like this(x3)3+(y3)3 then(x3+y3)(x6-x3y3+y6)but the book says the answer is(x+y)(x2-xy+y2)(x6-x3y3+y6) '

Explanation / Answer

Again book is right

you did:

(x3)3+(y3)3 then(x3+y3)(x6-x3y3+y6)

if u see clearly in questn then u will notice that theterm (x3+y3) can again be factorizedas:

=> (x3+y3) =(x+y)(x2-xy+y2)

so the final answer will be;

x9+y9 =(x+y).(x2-xy+y2).(x6-x3y3+y6) That is thebook answer