Find an equation of the line that bisects theobtuse angles formed by the lines w

Question

Find an equation of the line that bisects theobtuse angles formed by the lines with equations 3x-y=1 andx+y=-2. a. (32+10)x-(10+ 2)y-210+2=0 b. (32- 10)x+(10- 2)y+210+2=0 c. (32+ 10)x+(10 - 2)y+210- 2=0 d. (32+ 10)x-(10+ 2)y-210-2=0 a. (32+10)x-(10+ 2)y-210+2=0 b. (32- 10)x+(10- 2)y+210+2=0 c. (32+ 10)x+(10 - 2)y+210- 2=0 d. (32+ 10)x-(10+ 2)y-210-2=0

Explanation / Answer

Find an equation of the line that bisects theobtuse angles formed by the lines with equations 3x-y=1 andx+y=-2. 3x-y=1 ==> y= 3x-1; m = 3 and x+y= -2 ==> y = -x -2; m = -1 an equation of the line that bisects the obtuse angles has slope m = 1 because (3+-1)/2 Find the intersection point: 3x-1 = -x-2 4x=-1 x = -1/4; y = 1/4-2= -7/4 Equation: y - -7/4 = 1( x- -1/4) y+ 7/4 = x + 1/4 y = x -3/2

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