Find k if the two straight lines are parallel. 4x-ky=6 6x+3y+2=0 Help!! Solution

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First rewrite the equations:     4x - ky = 6 =>     4x - 6 = ky =>     y = (4/k)x - 6/k     6x + 3y + 2 = 0 =>     6x + 2 = -3y => y = -2x - 2/3 The slope of a line with an equation of the form y = mx + c ism. When two lines are parallel, their slopes are equal. So if y= (4/k)x - 6/k is parallel to y = -2x - 2/3, then 4/k = -2 =>     k = -2 => (4/k)x - 6/k = -2x + 3 Check: Graph y = -2x + 3 and y = -2x - 2/3 to verify that they are in factparallel. If you find this post helpful, please rate it.

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