A pump removes 1000 gal. of water from a pool at acoonstant rate of 50gal/min. a

Question

A pump removes 1000 gal. of water from a pool at acoonstant rate of 50gal/min. a. Write a equation to find the amount of water y in the poolafter t minutes. b. Interpret the t- and y- intercepts. Help... are any of these answers right? y=50t-1000 or 1000y=50t What's the correct answer!? A pump removes 1000 gal. of water from a pool at acoonstant rate of 50gal/min. a. Write a equation to find the amount of water y in the poolafter t minutes. b. Interpret the t- and y- intercepts. Help... are any of these answers right? y=50t-1000 or 1000y=50t What's the correct answer!?

Explanation / Answer

Let's consider your first possible answer, y =50t-1000 . When you're trying to translate a word problem into anequation and want to check your answer, try plugging in a couple ofpoints where you know the answer and see if they work. Weknow that at the beginning, when t = 0, there are 1000 gallons ofwater in the pool. What happens if we plug t=0 into yoursuspected answer? We get y = -1000. This is notcorrect. So let's start over. . When you're trying to put together a line, a good startingpoint is its Y-intercept, the value of Y when x (or, in this case,t) is 0. The problem gives us this value; the pool startswith 1000 gallons. So we know that Y = 1000 + something,where the something is the part that will tell us how the valuechanges as we change t. . How does the value change as we change t? Well, everytime one minute passes (that is, every time t goes up by 1), welose 50 gallons from the pool. So we want to subtract 50times the number of minutes that have passed. . Can you finish it from here?

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