question: a piece of wire 48cm long is cut into two pcs.,each tobe bent to make

Question

question: a piece of wire 48cm long is cut into two pcs.,each tobe bent to make a square.the lenght of a side of one square is tobe 4 cm longer thatn the lenght of the other.how should the wire becut? a) the lenght ogf the shorter pc of wire is???? cm b)the lenght of the longer pc of wire is????    cm PLEASE SHOW ME STEP BY STEP TO SOLVE THIS. I KNOW I HAVETO X AS ONE SQUARE AND X+4 AS THE OTHER.   SOMEHOW THEFORMULA GOES 4X+4X+24=?? THEN I KNOW I I HAVE TO DO SOME DIVIDEDING AND MULTIPLYING,PLEASE SHOW STEP BY STEP     THANKS! question: a piece of wire 48cm long is cut into two pcs.,each tobe bent to make a square.the lenght of a side of one square is tobe 4 cm longer thatn the lenght of the other.how should the wire becut? a) the lenght ogf the shorter pc of wire is???? cm b)the lenght of the longer pc of wire is????    cm PLEASE SHOW ME STEP BY STEP TO SOLVE THIS. I KNOW I HAVETO X AS ONE SQUARE AND X+4 AS THE OTHER.   SOMEHOW THEFORMULA GOES 4X+4X+24=?? THEN I KNOW I I HAVE TO DO SOME DIVIDEDING AND MULTIPLYING,PLEASE SHOW STEP BY STEP     THANKS!

Explanation / Answer

    x = the length of a side of thesmaller square     PS = the perimeter of thesmaller square = 4x     x + 4 = the length of aside of the larger square     PL = the perimeter of thelarger square = 4(x + 4) = 4x + 16     (4x) + (4x + 16) = 48 =>     8x + 16 = 48 =>     8x = 32 =>     x = 32 / 8 = 4 cm (a) The length of the shorter piece of wire is:     PS = 4(4) = 16 cm (b) The length of the larger piece of wire is:     PL = 4(4) + 16 = 32 cm

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