for these data :13,15,21,20,14,14,22,18,22,24,20,24,23,17,23,22,22,16,15,16,17,2
ID: 3094593 • Letter: F
Question
for these data :13,15,21,20,14,14,22,18,22,24,20,24,23,17,23,22,22,16,15,16,17,21,16,22,21,23 we need present these data as a bar graph and as a table what is the value of the mean of the data presentedabove? what are the median and the range of data presentedabove? for these data :13,15,21,20,14,14,22,18,22,24,20,24,23,17,23,22,22,16,15,16,17,21,16,22,21,23 we need present these data as a bar graph and as a table what is the value of the mean of the data presentedabove? what are the median and the range of data presentedabove?Explanation / Answer
The mean is the average of all of the values. To find theaverage value, take the sum of the data points, and divide by thenumber of data points, or: 501/26 =19.27 The median is the value that is in the middle (or the average ofthe middle two for an even-numbered set of values). Since youhave 26 data points, you will need to find the average value of the13th and 14th data points. Rearranging the data points, youhave 13, 14, 14, 15, 15, 16, 16, 16, 17, 17, 18, 20, 20, 21, 21,21, 22, 22, 22, 22, 22, 23, 23, 23, 24, 24. The middle two values are 20 and 21 (the 13th and 14th points outof 26). Therefore, the median is the average, or20.5. The range of data is 13 to 24. (Preparing a bar graph, you would have an x-axis with the datapoint values, and a y-axis with the frequency the numbersoccur.) Therefore, you would have bars for 0 - 12 with a height of 0 (or you could omit them from the graph altogether), abar for 13 with a height of 1, a bar for 14 with a height of 2, abar for 15 with a height of 2, a bar for 16 with a height of 3,etc. Not sure how they want a table arranged, but I'd suggest a 2 x 13table with the points (in the order that you originallypresented). Hope this helps.
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