Hi can someone help me figure this out? On a morning of a day when the sun will

Question

Hi can someone help me figure this out? On a morning of a day when the sun will pass directlyoverhead, the shadow of an 80 ft. building on level ground is 60 ftlong as shown in the figure. At the moment in question, the angle,theta, the sun makes with the ground is increasing at the rate of0.27 degrees/minute. At what rate is the shadow length decreasing?Express your answer in inches/minute, to the nearest tenth.(Remember to use radians) This is problem number 33 in page 253 in the Finney textbook,3rd edition Hi can someone help me figure this out? On a morning of a day when the sun will pass directlyoverhead, the shadow of an 80 ft. building on level ground is 60 ftlong as shown in the figure. At the moment in question, the angle,theta, the sun makes with the ground is increasing at the rate of0.27 degrees/minute. At what rate is the shadow length decreasing?Express your answer in inches/minute, to the nearest tenth.(Remember to use radians) This is problem number 33 in page 253 in the Finney textbook,3rd edition

Explanation / Answer

tan = 80/x d/dt=.27 deg/min=.00488692 rad/min when x= 60 , tan =80/60 or =arctan (4/3)= .927 rad taking derivative of first equation sec2 d/dt=80(-2)x-2 dx/dt sec2.927=2.7777=-160/3600 dx/dt -62.4998=dx/dt The problem would have more solutions submitted in the calculusQA

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