A box has rectangle sides and a rectangle top and base thatare twice as long as
ID: 3096037 • Letter: A
Question
A box has rectangle sides and a rectangle top and base thatare twice as long as they are wide.The volume of the box is 588cubic inches,and the surface area of the outside of the boxis 448 square inches.Find the dimensions of the box.please show me how and the answer thanks A box has rectangle sides and a rectangle top and base thatare twice as long as they are wide.The volume of the box is 588cubic inches,and the surface area of the outside of the boxis 448 square inches.Find the dimensions of the box. please show me how and the answer thanks
Explanation / Answer
Sides are x, 2x, and z. You have the surface area equation 2xz + 4xz + 4x^2 = 448, and the area equation 2(x^2)z = 588. Solve for z = 588 / (2x^2). Plug z into the surface area equation and you will get x^3 - 112x + 441 = 0. Put this into a graphing calculator and you will get x = 7. So your dimensions for the box are 7, 14, and 6.
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