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Trying to solve (2 - 2x)^2 / (1.5 - x)(3 - 3x)^3 I got a large denominator, (27x

ID: 3098221 • Letter: T

Question

Trying to solve                      (2 - 2x)^2 / (1.5 - x)(3 - 3x)^3 I got a large denominator, (27x^4 - 40.5x^3 + 129.5x^2 -148.5x + 40.5), and my numerator was (4x^2 + 8x + 4) i dont know where to go from here. Do i long divide this or can i factor this out by simplifying more. help is very welcomed Trying to solve                      (2 - 2x)^2 / (1.5 - x)(3 - 3x)^3 I got a large denominator, (27x^4 - 40.5x^3 + 129.5x^2 -148.5x + 40.5), and my numerator was (4x^2 + 8x + 4) i dont know where to go from here. Do i long divide this or can i factor this out by simplifying more. help is very welcomed

Explanation / Answer

2^2(1-x)^2/{(1.5-x)(3^3)1-x)^(3)} 4/{27(1.5-x)(1-x)} try factoring initially, then simplify

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