Use sign chart to solve the inequalities below: a. 2x^3-24x< b. (x-5)/(3x+1) is

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a. It isn't showing what it is less than so I can't help you with this one, if you correct it to show that, I can help you. b. (x-5)/(3x+1) is greater than or equal to 4: first you should set the equation equal to 4 and solve for all real values of x, this will give you all the times when the equation is equal to 4: (x-5)/(3x+1) = 4 >>> multiply both sides by (3x+1) x-5 = 12x + 4 >>> get all the x's to one side and all the other numbers to the other side -11x = 9 >>> solve for x x = -9/11 So now we know that x = 4 at -9/11, so we know that on either side of this number, from -9/11 to infinity, and from -9/11 to negative infinity, all the numbers are either greater than 4, or less than 4. To figure out which it is, we take a number from either side and plug it into our equation. I'll use -1 (less than -9/11) and 0 (greater than -9/11): y = (x-5)/(3x+1) >>> plug in -1 y = (-1-5)/(3*-1+1) >>> simplify y = (-6)/(-2) = 3 (less than 4) So now we know all values of x less than -9/11 are less than 4. y = (x-5)/(3x+1) >>> plug in 0 y = (0-5)/(3*0+1) >>> simplify y = (-5)/(1) = -5 (less than 4) So now we know that the graph is less than four on both sides of x = -9/11 so we can make the sign chart with this knowledge.

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