1) (36m^4 n^6)^0.5 (81m^12 n^8)^0.25 I do not get why the answer is 18 m^5 n^5 I
ID: 3098997 • Letter: 1
Question
1) (36m^4 n^6)^0.5 (81m^12 n^8)^0.25I do not get why the answer is 18 m^5 n^5
I got the m^5 and n^5 but I do not get how they got 18..
cuz I got 19..
2) (((v64a^12)/(a^1.5)^6))^2/3
I do not get a why the answer is 4a^14
I got the answer as 4 but I do not get the why the answer is a^10
thank you..
1) (36m^4 n^6)^0.5 (81m^12 n^8)^0.25 I do not get why the answer is 18 m^5 n^5 I got the m^5 and n^5 but I do not get how they got 18.. cuz I got 19.. 2) (((v64a^12)/(a^1.5)^6))^2/3 I do not get a why the answer is 4a^14 I got the answer as 4 but I do not get the why the answer is a^10 thank you..
Explanation / Answer
d = rtmake a simple chart
Distance Rate Time
trip 1 2x ? 3h
trip 2 x+10 ? 2h
Solve both trips for rate/speed
2x = r(3h)
r = (2x)/(3h)
(x+10) = r(2h)
r = (x+10)/(2h)
Part A
Asks to find the difference of speed_1 and speed_2
(2x)/(3h) - ( (x+100)/(2h) ) To subtract, you must have like denominators multiply first term by 2 multiply second term by 3 (4x)/(6h) - ( (3x+100)/(6h) ) now combine (4x+3x+100)/(6h) Add to find the final expression (7x+100)/(6h)
I will try to post part b if I have time
Sorry
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