USE THIS PORTION TO SOLVE THE PROBLEM BELOW labled golden painting. I only need
ID: 3102562 • Letter: U
Question
USE THIS PORTION TO SOLVE THE PROBLEM BELOW labled golden painting. I only need the second portion answered.Golden Rectangle. One principle used by the ancient
Greeks to get shapes that are pleasing to the eye in art
and architecture was the Golden Rectangle. If a square
is removed from one end of a Golden Rectangle, as shown
in the figure, the sides of the remaining rectangle are
proportional to the original rectangle. So the length
and width of the original rectangle satisfy
L/W=W/L-W
Golden painting. An artist wants her painting to be in the
shape of a golden rectangle. If the length of the painting is
36 inches, then what should be the width? See the previous
exercise.
Explanation / Answer
36/W = W/(36-W) 36 = W^2/(36-W) 36(36-W) = W^2 1296-36W=W^2 1296 = W^2+36W W^2+36W-1296 = 0 solve for W you should get 22.249224
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