Write the equation of the line with a slope of -5 and a y-intercept of (0,3). Wr

Question

Write the equation of the line with a slope of -5 and a y-intercept of (0,3).

Write the equation of the line with a slope of -1/3 and passing through the point (6, -4).

Write the equation of the line passing through the points (0, -4) and (-2, 2).

Write the equation of the line passing through the points (-6,1) and (-4,2).

Write the equation of the line with an undefined slope, passing through the point (2, 5). Hint: refer back to lesson 4.04 for help with this one.

Write the equation of the line on the following graph.

Explanation / Answer

a) Y=mx+b 3=-5(0)+b 3=b y=-5x+3 b)Y=mx+b -4=(-1/3)(6)+b -4=-2+b b=-2 y=(-1/3x)-2 C)first find the slope (y^2-y^1)/(x^2-x^1)=m which will equal -3 you then take (0,-4) and -3 and put them into y=mx+b solve for b -4=(-3)(0)+b -4=b y=-3x-4 D) again find the slope (y^2-y^1)/(x^2-x^1)=m whihc will equal 1/2 then plug in for y=mx+b (1/2)(-6)+b=1 -3+b=1 b=4 so y=(1/2)x+4 E)x=2, becuase it has no defined slope, and must be vertical F)graph didn't show

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