When a bullet is fired straight up with muzzle velocity 800 ft/s. its height abo

Question

When a bullet is fired straight up with muzzle velocity 800 ft/s. its height above the ground after t seconds is given by the function h(t) = 800t - 16t^2...

I need step by step on how to enter this correctly. If I am thinking right, it should be a parabola but when I enter it into the plot and graph it, it is more of a scatter.

Also -- the rest of my problem wants me to tell maximum height, falling back to ground level, etc. But the graphing calculator has no numbers to tell me.

I know this is basic stuff, but I really need some help -- so thanks!!

Explanation / Answer

If you are using a TI-83 or TI-84 just go to [Y=] and enter [8][0][0][-][1][6][x][x2] and press [graph] and now go to [window] change Xmin to 0; Xmax to 50; Ymin to 0; Ymax to 12000 and now press [graph] again

if you did it correctly, you should see a nice parabola

and now to find the maximum

press [2nd][trace][4]which says maximum

and now press the left arrow key to move to the left of the peak to set the left boundary and press [enter]

and use the right arrow key to move to the right of the peak to set the right bounday and press [enter]

and press [enter] again and it should show on your calculator the maximum value of x and y

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