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Below are four graphs of the position function y(t) over time for harmonic oscil

ID: 3110317 • Letter: B

Question

Below are four graphs of the position function y(t) over time for harmonic oscillators with initial conditions y(0) = 1, y'(0) = 0. Of the eight given equations, choose the four equations that match the graphs, and briefly justify (1-2 phrases) in the space under each graph. (Remark: You should not need to solve the eight equations.) (i) y" + y = 0 (ii) y" + 2y' + y = cos (2t) (iii) y" + 2y' + y = e^2t (iv) 2y" - y'+ 10y = 0 (v) 2y" + y' +10y = 0 (vi) y" + 9y = cos (3t) (vii) y" + 9y = e^-3t (viii) y" + 11y = cos (3t)

Explanation / Answer

(a) The graph matches with the differential equation (v) 2y"+y'+10y=0

It seems like the case of underdamped system.

(b)The graph matches with the differential equation (vii) y"+9y=e^(-3t)

As the time goes on increasing the effect of e^(-3t) keeps on decreasing leading the solution influenced by only sine and cosine terms.

(c)The graph matches with the differential equation (i) y"+y=0

It is our undamped, unforced harmonic oscillator, This has pure periodic solutions. Cosx may be the function.

(d)The graph matches with the differential equation (vii) y"+11y=cos3t

11 is close to 3, Beat will be present.

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