a chemist needs 8 liters of a 50% salt solution. All she has available is a 20%

Question

a chemist needs 8 liters of a 50% salt solution. All she has available is a 20% Salt solution and a 70% Salt solution. how much of each of the two solutions should she mix to obtain her desired solution? a chemist needs 8 liters of a 50% salt solution. All she has available is a 20% Salt solution and a 70% Salt solution. how much of each of the two solutions should she mix to obtain her desired solution? a chemist needs 8 liters of a 50% salt solution. All she has available is a 20% Salt solution and a 70% Salt solution. how much of each of the two solutions should she mix to obtain her desired solution?

Explanation / Answer

Let x = the amount of 20% solution and  y = the amount of 70% solution

x+y=8 (the total amount of the 50% solution being equal to 8 liters)
=> y=8-x

0.2x+0.7(8-x)=0.5(8)=4

Multiplying the equation by 10
2x+7(8-x)=40
2x+56-7x=40
-5x+56=40
-5x=-16

x = 3.2 , y =  4.8

Hence, we need to combine 3.2 liters of 20% and 4.8 liters of 70% solutions to get 8 liters of 50% solution.

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