If 25,000 is invested in an account paying 5.5% interest compounded continuously

Question

If 25,000 is invested in an account paying 5.5% interest compounded continuously, used the formula A = P^nt to calculate how much there will be in the account in layers. Write 2^6 = 6^4 in logarithms form Use the change of base formula to evaluate log_11^29 change of base formula logo x = log x/log b Use properties of logarithms to expand log ((x+3)^2 (x-1)^5/(x+2)^3) Solve for x: 2^3x-8 = 14 Solve for x: log_2 x + log_2(x-7) = 3 Use the fact that after 5715 years a given amount of carbon 14 will have decayed to half the original amount to find the experiential decay model for carbon 14 use A= A_0e^kt Find the vertex of the parabola F(x) = x^2 - 2x - 2y Find the x-intercepts of the parabola f(x) = x^2 - 2x - 2y

Explanation / Answer

1) A = P ert
P= 25,000
r= 5.5% = 0.055
t= 10 years
A = 25,000 * e0.055*10
A = 25,000 * e0.55
A = 25,000 * 1.733
A = 43,325$
The amount will be 43,325 after 10 years


2) if 26 = 64
Take log on both side and we get
log 26 = log 64
log am = m log a
applying the formula we get:
6 log 2 = log 64
or 6 = log 64/ log 2
or
6 = log 2 64 ;

3) log 11 29 = log 29/log 11 = 1.4623/ 1.0143 = 1.4416;

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