Two recording devices are set 2600 feet apart, with the device at point A to the

Question

Two recording devices are set 2600 feet apart, with the device at point A to the west of the device at point B. At a point on a line between the devices, 300 feet from point B, a small amount of explosive is detonated. The recording devices record the time the sound reaches each one. How far directly north of site B should a second explosion be done so that the measured time difference recorded by the devices is the same as that for the first detonation? 690 feet 1362.39 feet 3502.38 feet 1264.91 feet

Explanation / Answer

Considering your measuring point (P) is 2300 from A and 300 from B the time difference between the two will be

2300-300 = 2000.
You need a new point (C) directly north of B a distance x (which creates a right angle triangle).
Using Pythagorean, (x+2000)^2=x^2+2600^2 solve for x.

x=690

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.