The world population at the beginning of 1990 was 5.3 billion. Assume that the p
ID: 3113889 • Letter: T
Question
The world population at the beginning of 1990 was 5.3 billion. Assume that the population continues to grow at the rate of approximately 2.7%/year and find the function Q(t) that expresses the world population (in billions) as a function of time t (in years), with t = 0 corresponding to the beginning of 1990. Using this function, complete the following table of values. (Round your answers to one decimal place.)
The world population at the beginning of 1990 was 5.3 billion. Assume that the population continues to grow at the rate of approximately 2.7%/year and find the function Q(t) that expresses the world population (in billions) as a function of time t (in years), with t0 corresponding to the beginning of 1990. Using this function, complete the following table of values. (Round your answers to one decimal place.) Year World Population 1990 1995 2000 2005 2010 2015 2020 2025 billion billion billion billion billion billion billion billionExplanation / Answer
At the beginning of 1990 was 5.3 billion rate 2.7/year .
S.NO Time Year Population
1 0 1990 5.3 billion
2 5 yr 1990-1995 (2.7/100)*(5.3*10^9)*5 = .71*10^9
{5.3*10^9 +.71*10^9} = 6.016*10^9
3 5yr 1995-2000 (2.7/100)*(6.016*10^9)*5 = .812*10^9
{ .812*10^9 + 6.016*10^9 } = 6.818*10^9
4 5yr 2000-2005 (2.7/100)*(6.818*10^9)*5 = .92*10^9
{ .812*10^9 + 6.818*10^9 } = 7.74*10^9
5 5yr 2005-2010 (2.7/100)*(7.74*10^9)*5 = 1.04*10^9
{1.04*10^9 + 7.74*10^9} = 8.78*10^9
6 5yr 2010-2015 (2.7/100)*(8.78*10^9)*5 = 1.18*10^9
{1.18*10^9 + 8.78*10^9} = 9.96*10^9
7 5yr 2015-2020 (2.7/100)*(9.96*10^9)*5 = 1.34*10^9
{1.34*10^9 + 9.96*10^9} = 11.30*10^9
8 5yr 2020-2025 (2.7/100)*(11.30*10^9)*5 = 1.52*10^9
{1.52*10^9 + 11.30*10^9} = 12.82*10^9
Answer for every 5 year
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