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Dear Student Thank you for using Chegg !! Given matrix a 1 d Matrix 1 det b 1 e = 4 c 1 f a 1 d Matrix 2 det b 2 e = -3 c 3 f a) a 1 d Matrix 3 det b 1 e = ? c 1 f Multiplying determinant of Matrix 1 by 6 => As per determinant properties , 1 of the rows or columns gets multiplied by 6 => It becomes equivalent to Matrix 3 Hence the value of determinant of Matrix 3 becomes 24 b) a 2 d Matrix 4 det b 5 e = ? c 8 f Multiplying determinant of Matrix 2 by 3 => As per determinant properties , 1 of the rows or columns gets multiplied by 3 Now the matrix 2 becomes as below a 3 d det b 6 e = -9 c 9 f Now subtracting matrix 1 from above matrix we get a 2 d det b 5 e = -13 c 8 f Solution

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