Algebra 2 Unit 4 Test - va erlod 10 lf(x + 4)(x-6)-(x-A)\" + k·then what St. val

Question

Algebra 2 Unit 4 Test - va erlod 10 lf(x + 4)(x-6)-(x-A)" + k·then what St. val" of k , 14 What are the solutions to the Compare the axis of symmetry and the minium values for the two functions below )-4-21 Determine which of the following statements is correct is. Selve the following system foe the y-coordinaties of the system A The fanctions h(a) and Cx) have the same axis of symmetry, but the misimum value B. The fanctions A) and J(x) have the same axis of symmetry, but the minimum value C The funcrions b(x) and JCx) do not have the same axis of symmetry, and the minimum D. The functions AÇx) and J(x) do not have the same axis of symmetry, and the minimam o his less than the minimum value of x) of Acx)is greater than the minimam valus of a) value of hx)is less than the minimum value of x) value of hCis greater than the minimum value of ) Ay--13 and y 19 D. y-3 andy-19 12. Compare the finctions,f(x) and g(x), and explain how theaph off(x)-xa-4x+3 is related to the graph of gx)-r-4-5 A. (x) is vertically stretched to make gix) B f(x) is translated & units left to make sx) C x) is translated down 8 units to make g(x) D fx) is compressed vertically to make g(x) parabola has a vertex of (-3,2) and passes theough the point (4,7) y-alr-)+ 3. A In the form of the parabola, what is the value of a? A S 49 D. 49 144

Explanation / Answer

Given (x+4) (x - 6 ) = (x - h)^2 + k (x+4) (x - 6 ) = (x - h)^2 + k x^2 -2x - 24 Now completing the square we get x^2 - 2x + 1 - 1 - 24 (x - h)^2 + k (x - 1)^2 - 25 = (x - h)^2 + k Hence h = 1 k = -25 Solution

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