Someone is playing roulette until the first win. The probability to win in each
ID: 3121511 • Letter: S
Question
Someone is playing roulette until the first win. The probability to win in each round is p, the probability to is q = 1 - p. Find the probability that this person will play exactly once _______ twice _______ 3 times _______ 6 times _______ n times _______ Express your answer in terms of p and q. Find the conditional probability that there is a boy in a family with two kids if it is known that one of the children is girl _______. Find the conditional probability that there is it boy in a family with two kids if it is known that the first child is a girl _______. A point is randomly chosen in a square [0, 1] times [0, 1]. The event A is that the point is in a square with vertices (0, 0), (0, 1/2), (1/2, 1/2), (1/2, 0). The event B is that the point is in a square with vertices (1/4, 1/4), (1, 1/4), (1, 1), (1/4, 1). (See Fig. 1a). Find the probability^1 P(A) = P(B) = P(AB) = P(A or B) = P(A^e) = P(B^e) = P(A^e and B^e) = P((A or B)^e) = P(A|B) = P (B|A) = Are events A and B independent ? _______ A point is randomly chosen in a square [0, 1] times [0, 1]. The event A is that the point is in square with vertices (0, 0),(0, 1/2), (1/2, 1/2), (1/2, 0). The event B is that theExplanation / Answer
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Given a roulette wheel with probability of winning defined by p and probability of loosing defined y q.
Now
a) If the person played only 1 match and he leaves only after winning.
=> He won the first match played
Probability = p
b) Twice
=> The person lost his first match and won the second.
Probability = q X p
(By fundamental principle of multiplication, since both the events are happening in consequence hence their probabilities are multiplied.)
c) 3 Times
Person lost first 2 matches and won thrid.
Probability = q^2p
d) 6 Times
Probability = q^5p
e) n times
Probability = q^ (n-1) * p
Solution.
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