Is lambda = -3 an eigenvalue of A = [-1 6 4 9]? Why or why not? Choose the corre

Question

Is lambda = -3 an eigenvalue of A = [-1 6 4 9]? Why or why not? Choose the correct answer below. A. Yes, lambda is an eigenvalue of A because (A - lambda I) is invertible. B. Yes, lambda is an eigenvalue of A because Ax = lambda x has a nontrivial solution. C. No, lambda is not an eigenvalue of A because Ax = lambda x only has the trivial solution. D. No, lambda is not an eigenvalue of A because Ax = lambda x has a nontrivial solution. E. Yes, lambda is an eigenvalue of A because lambda Ax = 0 only has the trivial solution. F. No, lambda is not an eigenvalue of A because lambda Ax = 0 only has the trivial solution.

Explanation / Answer

Answer:

Yes =-3 is eignevalue of A

it can be obtained by = det (A-I) = (-1-) (9-) -6*4 =0

(2-8-9-24) =0

(2-8 -33) =0

= -3 and = 11

Now as for given option

(B) Yes , is an eigenvalue of A because Ax=x has nontiial solution :

Answer

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.