Homework: W5: Assignment 2 Homework Save Score: 3 of 6 pts 7 of 10 (8 complete)

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Homework: W5: Assignment 2 Homework Save Score: 3 of 6 pts 7 of 10 (8 complete) HW Score: 75.67%, 45.4 of 60 p E Question Help 8.4.28-T The accompanying data table lists measured voltage amounts supplied directly to a family's home. The power supply company states that it has a target power supply of 120 volts. Using those home voltage amounts, test the claim that the mean is 120 volts. Use a 0.05 significance level Click the icon to view the sample data. Data Table CD Click the icon to view a table of critical t-values. What are the null and alternative hypotheses? Full data set Day Volts Day Volts O A. o: H 120 Ho: H-1 20 124.1 124.0 H 120 H1: 120 23.9 22 23.9 C. Ho: H 120 Ho: H-1 20 23.9 23 23.6 HE 12 H1: H 120 124.5 24 23.9 123.4 25 123.4 Calculate the test statistic. 123.3 26 123.4 123.3 27 123.4 79.811 Round to three decimal places as needed.) 23.6 28 123.4 What is the range of values for the P-value? 123.5 29 123.3 10 124.1 30 124.2 Choose the correct answer below. 11 123.5 123.5 123.7 32 123.6 B. P-value 0.20 A. 0.025 P-value

Explanation / Answer

Set Up Hypothesis
Null, H0: U=120
Alternate, H1: U!=120
Test Statistic
Population Mean(U)=120
Sample X(Mean)=123.7513
Standard Deviation(S.D)=0.2974
Number (n)=40
we use Test Statistic (t) = x-U/(s.d/Sqrt(n))
to =123.7513-120/(0.2974/Sqrt(40))
to =79.776
| to | =79.776
Critical Value
The Value of |t | with n-1 = 39 d.f is 2.023
We got |to| =79.776 & | t | =2.023
Make Decision
Hence Value of | to | > | t | and Here we Reject Ho
P-Value :Two Tailed ( double the one tail ) -Ha : ( P != 79.7757 ) = 0
Hence Value of P0.05 > 0,Here we Reject Ho

[ANSWERS]
Test statistic: to =79.776
P-Value = 0, P-value<0.01
Crtical value = -2.023, 2.023
Reject, suffcient

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