I am having a problem with these 2 questions: 1. At a sawmill in Oregon, a proce

Question

I am having a problem with these 2 questions:

1. At a sawmill in Oregon, a process improvement team measured the diameters for a sample of 1,500 logs. The following summary statistics were computed:

Q1 = 8.9" Q2 = 13.5"    Q3 = 15.6" Average = 14.2"

Given this information, which of the following statements is correct?

A. The distribution of log diameters is symmetric.

B. A log that is over 20 inches in diameter can be considered an outlier.

C. The distribution of log diameters is right-skewed.

D. The distribution is left-skewed.

2. Under what circumstances is it necessary to use the coefficient of variation to compare relative variability between two or more distributions?

A. When the means of the distributions are equal

B. When the means of the distributions are not equal

C. When the standard deviations of the distributions are not equal

D. When the standard deviations of the distributions are equal

A. The distribution of log diameters is symmetric.

B. A log that is over 20 inches in diameter can be considered an outlier.

C. The distribution of log diameters is right-skewed.

D. The distribution is left-skewed.

Explanation / Answer

2) The coefficient of variation is a measure of spread that describes the amount of variability relative to the mean. Because the coefficient of variation is unitless, you can use it instead of the standard deviation to compare the spread of data sets that have different units or different means.

Option B is correct

1)

Median value = Q2 = 13.5

Mean = 14.2

Thus, mean > median

So, the data is right skewed.

Hope this helps. Ask if you have doubts.

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.