Save Score: 0.44 of 1 pt 5 0.6 (3 complete) HW Score: 61.57%, 3 69 of 6 pts 10.4
ID: 3124455 • Letter: S
Question
Save Score: 0.44 of 1 pt 5 0.6 (3 complete) HW Score: 61.57%, 3 69 of 6 pts 10.4.16-T Question Help I * Suppose the mean wait-time for a telephone reservation agent at a large airline is 43 seconds. A manager with the airline is concemed that business may be lost due to customers having to wait too long for an agent. To address this concem, the manager develops new airfine reservation policies that are intended to reduce the amount of time an agent needs to spend with each customer. A random sample of 250 customers results in a sample mean wait-time of 42.3 seconds with a standard deviation of 43 seconds. Using :0.05 level of significance, do you believe the new policies were effective in reducing wait time? Do you think the results have any practical significance? Determine the null and altemative hypothes es Ho 43 seconds H1 : (43 seconds Calculate the test statistic. Round to two decimal places as needed) Enter your answer in the answer box and then click Check Answer Check Answer Clear All parts remainingExplanation / Answer
10.4.16
t Test for Hypothesis of the Mean
Data
Null Hypothesis m=
43
Level of Significance
0.05
Sample Size
250
Sample Mean
42.3
Sample Standard Deviation
4.3
Intermediate Calculations
Standard Error of the Mean
0.2720
Degrees of Freedom
249
t Test Statistic
-2.5739
Lower-Tail Test
Lower Critical Value
-1.6510
p-Value
0.0053
Reject the null hypothesis
Calculated t= -2.57 ( two decimals)
10.4.12
t Test for Hypothesis of the Mean
Data
Null Hypothesis m=
6
Level of Significance
0.1
Sample Size
49
Sample Mean
5.35
Sample Standard Deviation
2.4
Intermediate Calculations
Standard Error of the Mean
0.3429
Degrees of Freedom
48
t Test Statistic
-1.8958
Lower-Tail Test
Lower Critical Value
-1.2994
p-Value
0.0320
Reject the null hypothesis
Calculated t= -1.90 ( two decimals)
t Test for Hypothesis of the Mean
Data
Null Hypothesis m=
43
Level of Significance
0.05
Sample Size
250
Sample Mean
42.3
Sample Standard Deviation
4.3
Intermediate Calculations
Standard Error of the Mean
0.2720
Degrees of Freedom
249
t Test Statistic
-2.5739
Lower-Tail Test
Lower Critical Value
-1.6510
p-Value
0.0053
Reject the null hypothesis
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