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dit View History Bookmarks People Window Help O O 0 Take a Test Britt https://www.mathxl.com/Student/PlayerTest.aspx?testId=123899380&ce; Quiz: 09 Quiz Chapter 5 (part 3) This Question: 3 pts I 1 013(0 comple Use the Normal model N(1176,69) for the weights of steers. a) What weight represents the 63rd percentile? b) What weight represents the 92nd percentile? c) What's the IQR of the weights of these steers a) The weight representing the 63rd percentile is [ ] pounds. (Round to the nearest whole number as needed.) b) The weight representing the 92nd percentile is pounds. Round to the nearest whole number as needed.) c) The IQR for the weights of these steers is pounds. (Round to the nearest whole number as needed.)Explanation / Answer
A)
First, we get the z score from the given left tailed area. As
Left tailed area = 0.63
Then, using table or technology,
z = 0.331853346
As x = u + z * s,
where
u = mean = 1176
z = the critical z score = 0.331853346
s = standard deviation = 69
Then
x = critical value = 1198.897881 = 1199 [ANSWER]
**************
b)
First, we get the z score from the given left tailed area. As
Left tailed area = 0.92
Then, using table or technology,
z = 1.40507156
As x = u + z * s,
where
u = mean = 1176
z = the critical z score = 1.40507156
s = standard deviation = 69
Then
x = critical value = 1272.949938 = 1273 [ANSWER]
*****************
c)
For Q1:
First, we get the z score from the given left tailed area. As
Left tailed area = 0.25
Then, using table or technology,
z = -0.67448975
As x = u + z * s,
where
u = mean = 1176
z = the critical z score = -0.67448975
s = standard deviation = 69
Then
x = Q1 = critical value = 1129.460207
*******
For Q3:
First, we get the z score from the given left tailed area. As
Left tailed area = 0.75
Then, using table or technology,
z = 0.67448975
As x = u + z * s,
where
u = mean = 1176
z = the critical z score = 0.67448975
s = standard deviation = 69
Then
x = critical value = 1222.539793
****
Hence,
IQR = Q3 - Q1 = 1222.539793 - 1129.460207 = 93.079586
IQR = 93 [ANSWER]
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