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B https://www.mathod.com/Student/Player Test.aspxtestld 1238993798centerwin yes

ID: 3124738 • Letter: B

Question

B https://www.mathod.com/Student/Player Test.aspxtestld 1238993798centerwin yes dean Shahan 2/11/16 S:14 Quiz: 08 Quiz Chapter 5 (part 2) Submit Quiz This Qule 17 pts possible This Question: 8 pts Question Help What pencent of a standand Normal model is found in each region? Draw a picture rst c)-16 217 Find the percent of the area between 2-16and z 17 %Pound to two decanal places as needed ) d) Choose the corfect graph or j2 o D. Find te percent of the area in the negion Jel-08 %Pound to ivo deomsal places as needed Click to select your avens z Click to select your

Explanation / Answer

Note that the mean of the z distribution is at z = 0, and negative values of z are to its left, and positive values of z are to its right.

b)

For |z| > 0.8, it is actually z < -0.8 U z > 0.8.

Hence, it is

OPTION A. [ANSWER, CORRECT GRAPH]


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z1 = lower z score =    -0.8      
z2 = upper z score =     0.8      
          
Using table/technology, the left tailed areas between these z scores is          
          
P(z < z1) =    0.211855399      
P(z < z2) =    0.788144601      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.576289203      

Thus, those outside this interval is the complement =    0.423710797 = 42.37% [ANSWER]

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Note that if you use a table, the answer would be 42.38%, due to roundoff errors.