Need help with solving the below problem. Please show steps so I will understand

Question

Need help with solving the below problem. Please show steps so I will understand. In the week before and the week after a holiday, there were 12 comma 12,000 total deaths, and 5994 of them occurred in the week before the holiday.

a. Construct a 90% confidence interval estimate of the proportion of deaths in the week before the holiday to the total deaths in the week before and the week after the holiday.

b. Based on the result, does there appear to be any indication that people can temporarily postpone their death to survive the holiday?

a) ____< P < ____?

b) Based on the result, does there appear to be any indication that people can temporarily postpone their death to survive the holiday?

No, because the proportion could easily equal 0.5. The interval is not is not less than 0.5 the week before the holiday

Yes, because the proportion could not easily equal 0.5. The interval is substantially less than 0.5 the week before the holiday

Explanation / Answer

a.
CI = p ± Z a/2 Sqrt(p*(1-p)/n)))
x = Mean
n = Sample Size
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
CI = Confidence Interval
Mean(x)=5994
Sample Size(n)=12000
Sample proportion = x/n =0.5
Confidence Interval = [ 0.5 ±Z a/2 ( Sqrt ( 0.5*0.5) /12000)]
= [ 0.5 - 1.645* Sqrt(0) , 0.5 + 1.65* Sqrt(0) ]
= [ 0.492,0.508]

b.
Yes, because the proportion could not easily equal 0.5. The interval
is substantially less than 0.5 the week before the holiday

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