Assume that GRE Verbal scores approximate a normal curve with a mean of 500 and

Question

Assume that GRE Verbal scores approximate a normal curve with a mean of 500 and a standard deviation of 100.

4.1.   A university admissions office has decided to admit only those applicants who score in the top 25.14% of the GRE verbal distribution. In order to be admitted, a student must have received a score of ___________ or higher.

(I've given you some wiggle room in the final answer. Don't show any decimal places, e.g. 550.123 on your calculator should be entered as 550)
Please enter a whole number, with no decimal point.

Explanation / Answer

First, we get the z score from the given left tailed area. As          
          
Left tailed area =    0.7486      
          
Then, using table or technology,          
          
z =    0.670090658      
          
As x = u + z * s,          
          
where          
          
u = mean =    500      
z = the critical z score =    0.670090658      
s = standard deviation =    100      
          
Then          
          
x = critical value =    567.0090658 = 567 [ANSWER]         

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