The average mpg usage for a 2013 Toyota Prius for a sample of 10 tanks of gas wa
ID: 3125717 • Letter: T
Question
The average mpg usage for a 2013 Toyota Prius for a sample of 10 tanks of gas was 45.5 with a standard deviation of 1.8. For a 2013 Honda Insight, the average mpg usage for a sample of 10 tanks of gas was 42.0 with a standard deviation of 2.3. Assuming different population variances, at = 0.01, is the true mean mpg lower for the Honda Insight? Sample 1: Honda Insight Sample 2: Toyota Prius Which is the right hypotheses? Write the test statistic and critical value, test result (Decision), and Conclusion.
H0: µ1 = µ2
H1: µ1 µ2
H0: µ1 µ2
H1: µ1 > µ2
H0: µ1 µ2
H1: µ1 < µ2
H0: µd 0
H1: µd < 0
H0: µ1 = µ2
H1: µ1 µ2
H0: µ1 µ2
H1: µ1 > µ2
H0: µ1 µ2
H1: µ1 < µ2
H0: µd 0
H1: µd < 0
Explanation / Answer
Formulating the null and alternative hypotheses,
Ho: u1 - u2 >= 0
Ha: u1 - u2 < 0 [HYPOTHESES]]
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At level of significance = 0.01
As we can see, this is a left tailed test.
Calculating the means of each group,
X1 = 42
X2 = 45.5
Calculating the standard deviations of each group,
s1 = 2.3
s2 = 1.8
Thus, the standard error of their difference is, by using sD = sqrt(s1^2/n1 + s2^2/n2):
n1 = sample size of group 1 = 10
n2 = sample size of group 2 = 10
Thus, df = n1 + n2 - 2 = 18
Also, sD = 0.923579991
Thus, the t statistic will be
t = [X1 - X2 - uD]/sD = -3.78960137 [ANSWER, TEST STATISTIC]
where uD = hypothesized difference = 0
Now, the critical value for t is
tcrit = - 2.55237963 [CRITICAL VALUE]
Thus, as t < -2.5524, WE REJECT THE NULL HYPOTHESIS. [DECISION]
Hence, there is significant evidence at 0.01 level that the true mean mpg lower for the 2013 Honda Insight. [CONCLUSION]
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Hi! If you use another method/formula in calculating the degrees of freedom in this t-test, please resubmit this question together with the formula/method you use in determining the degrees of freedom. That way we can continue helping you! Thanks!
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