company knows that replacement times for the DVD players it produces are Normall
ID: 3126405 • Letter: C
Question
company knows that replacement times for the DVD players it produces are Normally distributed with a mean of 9.7 years and a standard deviation of 2.4 years.
Find the proportion of a randomly selected DVD players that will have a replacement time less than 3.7 years?
P(X < 3.7 years) =
Enter your answer accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
If the company wants to provide a warranty so that only 2.3% of the DVD players will be replaced before the warranty expires, what is the time length of the warranty?
warranty = years
Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Explanation / Answer
a)
We first get the z score for the critical value. As z = (x - u) / s, then as
x = critical value = 3.7
u = mean = 9.7
s = standard deviation = 2.4
Thus,
z = (x - u) / s = -2.5
Thus, using a table/technology, the left tailed area of this is
P(z < -2.5 ) = 0.006209665 [ANSWER]
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b)
First, we get the z score from the given left tailed area. As
Left tailed area = 0.023
Then, using table or technology,
z = -1.99539331
As x = u + z * s,
where
u = mean = 9.7
z = the critical z score = -1.99539331
s = standard deviation = 2.4
Then
x = critical value = 4.911056056 [ANSWER]
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