Assume the average weight of a full-term newborn infant (i.e. 39-40 weeks gestat
ID: 3128213 • Letter: A
Question
Assume the average weight of a full-term newborn infant (i.e. 39-40 weeks gestation) in the US is 3400g. Suppose we measure the birth weight of 1000 (full-term) infants born to alcoholic mothers. We find that the sample mean birth weight is 3200g, and the sample standard deviation is 500g.
a. Calculate a 95% confidence interval for the population mean birth weight of infants born to alcoholic mothers.
1.96*500sqrt(1000)= 30, 3200+/- 98= (3102,3298) <---- Is this right?
b. Suppose we want to test the hypothesis
H0: ? = 3400g
H1: ? ? 3400g
where ? is the population mean birth weight for offspring of alcoholic mothers. Using the confidence interval you calculated in (a), would you reject or fail to reject H0 at ? = 0.05? (Recall the close relationship between confidence intervals and hypothesis testing. Suppose you want to test a hypothesis H0: ? = ?o versus H1: ? ? ?o using ? = .05. You can test this hypothesis using a confidence interval with this rule: If ?o is OUTSIDE the 95% CI then REJECT the null hypothesis; if ?o is INSIDE the 95% CI then DO NOT REJECT the null hypothesis.)
The null would be rejected, correct?
c. Compute the following test statistic for the two-sided hypothesis test in part (b):
Is the p-value based on this test statistic less than 0.05?
I'm not sure how to go about doing this one...
X-HoExplanation / Answer
a)
Note that
Margin of Error E = z(alpha/2) * s / sqrt(n)
Lower Bound = X - z(alpha/2) * s / sqrt(n)
Upper Bound = X + z(alpha/2) * s / sqrt(n)
where
alpha/2 = (1 - confidence level)/2 = 0.025
X = sample mean = 3200
z(alpha/2) = critical z for the confidence interval = 1.959963985
s = sample standard deviation = 500
n = sample size = 1000
Thus,
Margin of Error E = 30.98975162
Lower bound = 3169.010248
Upper bound = 3230.989752
Thus, the confidence interval is
( 3169.010248 , 3230.989752 ) [ANSWER]
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