We count the number X of AB donors that come to a fixed Red Cross location per d

Question

We count the number X of AB donors that come to a fixed Red Cross location per day. This count has the Poisson distribution with parameter µ being the mean number of AB donors per day.

(a) The donation center sees an average of 2.1 AB donors per day. Find the Poisson probabilities for X = 0, 1, 2, 3, 4, 5 (for each number).

(b) What is the probability that this particular location would get more than 5 AB donors in one day?

This question is to be answered using R. R is a statistical computing program. I'm having trouble on finding what to input into the program.

Explanation / Answer

Generating Poisson Probabilities
a)Code for generating probabilities and output:-
dpois(0, lambda=2.1, log = FALSE)
0.1224564
dpois(1, lambda=2.1, log = FALSE)
0.2571585
dpois(2, lambda=2.1, log = FALSE)
0.2700164
dpois(3, lambda=2.1, log = FALSE)
0.1890115
dpois(4, lambda=2.1, log = FALSE)
0.09923104
dpois(5, lambda=2.1, log = FALSE)
0.04167704
Here lambda is the mean i.e. mu=2.1
b)Prob(more than 5)=1-P(less than & equal to 5)
R Code:-
1-ppois(5, lambda=2.1)
0.02044908
Note: #ppois represent less than & equal probability

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