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The following represent a sample of 24 measurements of the response time (in min

ID: 3130179 • Letter: T

Question

The following represent a sample of 24 measurements of the response time (in minutes) it takes the Help Desk to resolve software and hardware issues it received in a given month, answer the following questions: 54 35 31 27 81 74 11 19 1102961 35 94 31 26 12 128 14 30 78 52 36 20 44 Compute the mean time to resolve an issue; Compute the mode; Compute first quartile Ql. Explain what Q1 means; Compute the 75 h percentile. Explain what 75 h percentile means; Compute the standard deviation; Are there any outliers? Compute median; Draw a box-and wisher graph for this set of data Write down the last digit of your student ID in the (a). If the last digit of your student ID is an odd number, use 5 classes to construct a frequency distribution for this set of data, state the lower and upper class boundaries for each of the 5 classcs and construct the histogram; (b). If the last digit of your student ID is an even number (including 0), use 4 classes to construct a frequency distribution for this set of data, state the lower and upper class boundaries for each of the 4 classcs and construct the histogram; J. Based on what you got in (i) and using either the Empirical rule or the Chcbyshev's theorem, estimate how many of the response times should be within 2 standard deviations from the mean response time? k. Count from the sample exactly how many of the response times are actually within 2 standard deviations from the mean response time. 1. Explain why your answers from (j) and (k) arc the same or different?

Explanation / Answer

a)mean = sum of all/ total numbers

= 1132/24 = 47.16

b)mode is the one which has the highest frequency or repeatition hence there will be two modes here 31 and 35.

e)standard deviation =

g) median = mid term

as there are 24th term'median = (12th +13th term)/2

arranging in accending order = 11, 12, 14, 19, 20, 26, 27, 29, 30, 31, 31, 35, 35, 36, 44, 52, 54, 61, 74, 78, 81, 94, 110, 128

median = (35+35)/2 = 35

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