13. Refer to the following partial ANOVA table Source ss df MS F P-value Treatme
ID: 3130921 • Letter: 1
Question
13. Refer to the following partial ANOVA table
Source ss df MS F P-value
Treatment 717.40 3 9.173 .0442
Error 70.675
Total 1,848.20 19
a. The MS (mean square) for the treatments is ____
A. 239.133 B. 106.88 C. 1,130.8 D. impossible to ascertain
b. The F statistic is ______
A. 4.87 B. 3.38 C. 5.93 D. 6.91
c. The number of observations in the entire sample is ____
A. 20 B. 19 C. 22
d. The 5% critical value for the F test is
A. 2.46 B. 3.24 C. 3.38 D. impossible to ascertain
e. Our decision about the hypothesis of equal treatment means is that the null hypothesis
A. cannot be rejected at = .05.
B. can be rejected at = .05, but just barely.
C. can be rejected for any typical value of .
D. cannot be assessed from given information.
Explanation / Answer
a. MSTR=SSTR/(k-1)=717.40/3=239.133 (A)
b.F=MSTR/MSE=239.133/70.675=3.38 (B)
c.n=20 (A)
d. 3.24 (see F table with row 3 and column 16) (B).
e. The test statistic fall sin critical region, therefore, null hypothesis can be rejected at 0.05 level of significance. (B)
d.
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