A Live on Campus Live Off Campus, Not with Parents Live Off Campus, with Parents
ID: 3131737 • Letter: A
Question
A
Live on Campus
Live Off Campus,
Not with Parents
Live Off Campus,
with Parents
Total
Abstain
46
17
40
103
Light-Moderate
126
72
68
266
Moderate-Heavy
130
52
32
214
Total
302
141
140
583
study of drinking habits of college students produced the following table of counts:
a. Is this an observational or an experimental study? Explain briefly.
b. What proportion of students who live with their parents say that they abstain from drinking alcohol? Consider the following computer output for a chi-square test:
Expected counts are printed below observed counts Chi-Square contributions are printed below e
1 2 3 Total
1 46 17 40 103
53.36 24.91 24.73
1.015 2.512 9.429
2 126 72 68 266
137.79 64.33 63.88
1.009 0.914 0.266
3 130 52 32 214
110.85 51.76 51.39
3.308 0.001 7.316
Total 302 141 140 583
xpected counts
Chi-Sq 25.770, DF 4, P-Value 0.000 c. Show how to calculate the expected count for the “abstain from drinking/ reside off-campus with parents” cell of the table. d. What conclusion would you draw from this chi-square test? Explain briefly. e. Which cell contributes the most to the calculation of the chi-square statistic? What does this reveal about a possible relationship between a college student’s location of residence and drinking habits? Explain.
Live on Campus
Live Off Campus,
Not with Parents
Live Off Campus,
with Parents
Total
Abstain
46
17
40
103
Light-Moderate
126
72
68
266
Moderate-Heavy
130
52
32
214
Total
302
141
140
583
Explanation / Answer
This is an observational study because there is no intervention in the study and the two characteristic are observed.
Proportion p=40/140=0.2857
Expected counts are printed below observed counts Chi-Square contributions are printed below eexpected counts
1 2 3 Total
1 46 17 40 103
53.36 24.91 24.73
1.015 2.512 9.429
2 126 72 68 266
137.79 64.33 63.88
1.009 0.914 0.266
3 130 52 32 214
110.85 51.76 51.39
3.308 0.001 7.316
Total 302 141 140 583
Chi-Sq 25.770, DF 4, P-Value 0.000
c. Show how to calculate the expected count for the “abstain from drinking/ reside off-campus with parents” cell of the table.
Expected value =(140*103)/583 =24.73
d. What conclusion would you draw from this chi-square test? Explain briefly.
Calculated Chi-Sq 25.770, DF 4, P-Value 0.000 which is < 0.05 level of significance.
The null hypothesis is rejected.
There is significant association between drinking habits and living place of college students.
e. Which cell contributes the most to the calculation of the chi-square statistic?
cell of the table “abstain from drinking/ reside off-campus with parents” contribute more, the chi square value is 9.429
What does this reveal about a possible relationship between a college student’s location of residence and drinking habits? Explain.
There is significant association between drinking habits and living place of college students.
There is high abstain from drinking from the students reside off-campus with parents.
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