Your company is implementing a new drug testing policy. The test you have chosen

Question

Your company is implementing a new drug testing policy. The test you have chosen has a 3% chance of resulting n false negatives. In other words, 3% of the time, the individual still passes the test even though they actually have taken banned drugs. The test you have chosen also has an 8% chance of resulting in false positives. In other words, 8% of the time, the test incorrectly shows the individual falls the test even though they actually have not taken banned drugs. If you assume that 1% of the employees actually take banned drugs, what is the probability of any on randomly selected employee passing the test? How many individuals would you test each day to expect to find one that fails the test?

Explanation / Answer

P( passing the test ) = P(person has taken the drug)*P(false negtaives)+P(person has not taken drugs)*(1-P(false positives))

P(passing the test ) = 0.01*0.03+0.99*(1-0.08) = 0.9111

Since there is 0.9111 probability of finding an individual who passes the test, the probability that an individual fails the test will be given by,

P(fails the test) = 1-0.9111 = 0.0889

Thus to find one person who fails the test , test must be performed on 1/0.0889 or atleast 12 people.

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.