In the absence of special preparation, SAT mathematics (SATM) scores in 2013 var
ID: 3132475 • Letter: I
Question
In the absence of special preparation, SAT mathematics (SATM) scores in 2013 varied normally with population mean 514 and standard deviation 118. fifty students go through a rigorous training program designed to raise their satm scores by improving their mathematics skills. either by hand or by using the p-value of a test significance applet, carry out a test of a null hypothesis in each of the following situations with a standard deviation of 118.
A) The students average score is 541. Is this significant at the 5% level?
B) The students average score is 542. Is this significant at the 5% level?
Explanation / Answer
HERE WE WILL BE USING THE T TEST
A)WHERE H0=U = 514
HA= U>514
TEST STATIC = (X-MEAN)/(STANDARD DEV/SQRT(N))
MEAN = 514
X = 541
STANDARD DEV = 118
N = 50
APPLYING THE FORMULA = (541-514)/(118/SQRT(50)) = 1.61
THE DEGREE OF FREEDOM = 50-1 = 49
THE P VALUE WILL BE TAKEN FROM T TABLE = 0.0569
WHICH IS NOT SIGNIFICANT AT 5% HENCE REJECT NULL
B)
WHERE H0=U = 514
HA= U>514
TEST STATIC = (X-MEAN)/(STANDARD DEV/SQRT(N))
MEAN = 514
X = 542
STANDARD DEV = 118
N = 50
APPLYING THE FORMULA = (542-514)/(118/SQRT(50)) = 1.67
THE DEGREE OF FREEDOM = 50-1 = 49
THE P VALUE WILL BE TAKEN FROM T TABLE = 0.0506
WHICH IS NOT SIGNIFICANT AT 5% HENCE REJECT NULL
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.